t^2-1=1,5t

Solution for t^2-1=1,5t equation:

t^2-1=1.5t

We move all terms to the left:

t^2-1-(1.5t)=0

We add all the numbers together, and all the variables

t^2-(+1.5t)-1=0

We get rid of parentheses

t^2-1.5t-1=0

a = 1; b = -1.5; c = -1;
Δ = b2-4ac
Δ = -1.52-4·1·(-1)
Δ = 6.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.5)-\sqrt{6.25}}{2*1}=\frac{1.5-\sqrt{6.25}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.5)+\sqrt{6.25}}{2*1}=\frac{1.5+\sqrt{6.25}}{2}
$